-3x^2-22x-24=0

Solution for -3x^2-22x-24=0 equation:

-3x^2-22x-24=0

a = -3; b = -22; c = -24;
Δ = b2-4ac
Δ = -222-4·(-3)·(-24)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-14}{2*-3}=\frac{8}{-6}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+14}{2*-3}=\frac{36}{-6}
=-6
$